20y^2-5y+20=0

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Solution for 20y^2-5y+20=0 equation:



20y^2-5y+20=0
a = 20; b = -5; c = +20;
Δ = b2-4ac
Δ = -52-4·20·20
Δ = -1575
Delta is less than zero, so there is no solution for the equation

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